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x^2+x^2=2.89
We move all terms to the left:
x^2+x^2-(2.89)=0
We add all the numbers together, and all the variables
2x^2-2.89=0
a = 2; b = 0; c = -2.89;
Δ = b2-4ac
Δ = 02-4·2·(-2.89)
Δ = 23.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{23.12}}{2*2}=\frac{0-\sqrt{23.12}}{4} =-\frac{\sqrt{}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{23.12}}{2*2}=\frac{0+\sqrt{23.12}}{4} =\frac{\sqrt{}}{4} $
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